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0=8t^2-31t
We move all terms to the left:
0-(8t^2-31t)=0
We add all the numbers together, and all the variables
-(8t^2-31t)=0
We get rid of parentheses
-8t^2+31t=0
a = -8; b = 31; c = 0;
Δ = b2-4ac
Δ = 312-4·(-8)·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-31}{2*-8}=\frac{-62}{-16} =3+7/8 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+31}{2*-8}=\frac{0}{-16} =0 $
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